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authorsrichman333 <sarah_n_richman@brown.edu>2023-06-14 17:23:23 -0400
committersrichman333 <sarah_n_richman@brown.edu>2023-06-14 17:23:23 -0400
commitf0474c18d092f4db49255a1e92d7f052b7398897 (patch)
tree1e26ccaf42dec4d99904e2eddb36dff6f3b55948 /src/client/views/nodes/PhysicsBox/PhysicsSimulationQuestions.json
parent20d217d825891cf29a432a048d1f8e7bc04d062a (diff)
parentbf1198fbe73847087b1ec8e00a43306816b3508a (diff)
Merge branch 'master' into collaboration-sarah
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+{
+ "inclinePlane": [
+ {
+ "questionSetup": [
+ "There is a 1kg weight on an inclined plane. The plane is at a ",
+ " angle from the ground. The system is in equilibrium (the net force on the weight is 0)."
+ ],
+ "variablesForQuestionSetup": ["theta - max 45"],
+ "question": "What are the magnitudes and directions of the forces acting on the weight?",
+ "answerParts": [
+ "force of gravity",
+ "angle of gravity",
+ "normal force",
+ "angle of normal force",
+ "force of static friction",
+ "angle of static friction"
+ ],
+ "answerSolutionDescriptions": [
+ "9.81",
+ "270",
+ "solve normal force magnitude from wedge angle",
+ "solve normal force angle from wedge angle",
+ "solve static force magnitude from wedge angle given equilibrium",
+ "solve static force angle from wedge angle given equilibrium"
+ ],
+ "goal": "noMovement",
+ "hints": [
+ {
+ "description": "Direction of Force of Gravity",
+ "content": "The force of gravity acts in the negative y direction: 3π/2 rad."
+ },
+ {
+ "description": "Direction of Normal Force",
+ "content": "The normal force acts in the direction perpendicular to the incline plane: π/2-θ rad, where θ is the angle of the incline plane."
+ },
+ {
+ "description": "Direction of Force of Friction",
+ "content": "The force of friction acts in the direction along the incline plane: π-θ rad, where θ is the angle of the incline plane."
+ },
+ {
+ "description": "Magnitude of Force of Gravity",
+ "content": "The magnitude of the force of gravity is approximately 9.81."
+ },
+ {
+ "description": "Magnitude of Normal Force",
+ "content": "The magnitude of the normal force is equal to m*g*cos(θ), where θ is the angle of the incline plane."
+ },
+ {
+ "description": "Net Force in Equilibrium",
+ "content": "For the system to be in equilibrium, the sum of the x components of all forces must equal 0, and the sum of the y components of all forces must equal 0."
+ },
+ {
+ "description": "X Component of Normal Force",
+ "content": "The x component of the normal force is equal to m*g*cos(θ)*cos(π/2-θ), where θ is the angle of the incline plane."
+ },
+ {
+ "description": "X Component of Force of Friction",
+ "content": "Since the net force in the x direction must be 0, we know the magnitude of the x component of the friction force is m*g*cos(θ)*cos(π/2-θ)."
+ },
+ {
+ "description": "Y Component of Normal Force",
+ "content": "The y component of the normal force is equal to m*g*cos(θ)*sin(π/2-θ), where θ is the angle of the incline plane. The y component of gravity is equal to m*g"
+ },
+ {
+ "description": "Y Component of Force of Friction",
+ "content": "Since the net force in the x direction must be 0, we know the magnitude of the y component of the friction force is m*g-m*g*cos(θ)*sin(π/2-θ)."
+ },
+ {
+ "description": "Magnitude of Force of Friction",
+ "content": "Combining the x and y components of the friction force, we get the magnitude of the friction force is equal to sqrt((m*g*cos(θ)*cos(π/2-θ))^2 + (m*g-m*g*cos(θ)*sin(π/2-θ))^2)."
+ }
+ ]
+ },
+ {
+ "questionSetup": [
+ "There is a 1kg weight on an inclined plane. The plane is at a ",
+ " angle from the ground. The system is in equilibrium (the net force on the weight is 0)."
+ ],
+ "variablesForQuestionSetup": ["theta - max 45"],
+ "question": "What is the minimum coefficient of static friction?",
+ "answerParts": ["coefficient of static friction"],
+ "answerSolutionDescriptions": [
+ "solve minimum static coefficient from wedge angle given equilibrium"
+ ],
+ "goal": "noMovement",
+ "hints": [
+ {
+ "description": "Net Force in Equilibrium",
+ "content": "If the system is in equilibrium, the sum of the x components of all forces must equal 0. In this system, the normal force and force of static friction have non-zero x components."
+ },
+ {
+ "description": "X Component of Normal Force",
+ "content": "The x component of the normal force is equal to m*g*cos(θ)*cos(π/2-θ), where θ is the angle of the incline plane."
+ },
+ {
+ "description": "X Component of Force of Friction",
+ "content": "The x component of the force of static friction is equal to μ*m*g*cos(θ)*cos(π-θ), where θ is the angle of the incline plane."
+ },
+ {
+ "description": "Equation to Solve for Minimum Coefficient of Static Friction",
+ "content": "Since the net force in the x direction must be 0, we can solve the equation 0=m*g*cos(θ)*cos(π/2-θ)+μ*m*g*cos(θ)*cos(π-θ) for μ to find the minimum coefficient of static friction such that the system stays in equilibrium."
+ }
+ ]
+ },
+ {
+ "questionSetup": [
+ "There is a 1kg weight on an inclined plane. The coefficient of static friction is ",
+ ". The system is in equilibrium (the net force on the weight is 0)."
+ ],
+ "variablesForQuestionSetup": ["coefficient of static friction"],
+ "question": "What is the maximum angle of the plane from the ground?",
+ "answerParts": ["wedge angle"],
+ "answerSolutionDescriptions": [
+ "solve maximum wedge angle from coefficient of static friction given equilibrium"
+ ],
+ "goal": "noMovement",
+ "hints": [
+ {
+ "description": "Net Force in Equilibrium",
+ "content": "If the system is in equilibrium, the sum of the x components of all forces must equal 0. In this system, the normal force and force of static friction have non-zero x components."
+ },
+ {
+ "description": "X Component of Normal Force",
+ "content": "The x component of the normal force is equal to m*g*cos(θ)*cos(π/2-θ), where θ is the angle of the incline plane."
+ },
+ {
+ "description": "X Component of Force of Friction",
+ "content": "The x component of the force of static friction is equal to μ*m*g*cos(θ)*cos(π-θ), where θ is the angle of the incline plane."
+ },
+ {
+ "description": "Equation to Solve for Maximum Wedge Angle",
+ "content": "Since the net force in the x direction must be 0, we can solve the equation 0=m*g*cos(θ)*cos(π/2-θ)+μ*m*g*cos(θ)*cos(π-θ) for θ to find the maximum wedge angle such that the system stays in equilibrium."
+ },
+ {
+ "description": "Simplifying Equation to Solve for Maximum Wedge Angle",
+ "content": "Simplifying 0=m*g*cos(θ)*cos(π/2-θ)+μ*m*g*cos(θ)*cos(π-θ), we get cos(π/2-θ)=-μ*cos(π-θ)."
+ },
+ {
+ "description": "Simplifying Equation to Solve for Maximum Wedge Angle",
+ "content": "The cosine subtraction formula states that cos(A-B)=cos(A)*cos(B)+sin(A)sin(B)."
+ },
+ {
+ "description": "Simplifying Equation to Solve for Maximum Wedge Angle",
+ "content": "Applying the cosine subtraction formula to cos(π/2-θ)=-μ*cos(π-θ), we get cos(π/2)*cos(θ)+sin(π/2)*sin(θ)=-μ*(cos(π)cos(θ)+sin(π)sin(θ))."
+ },
+ {
+ "description": "Simplifying Equation to Solve for Maximum Wedge Angle",
+ "content": "Simplifying cos(π/2)*cos(θ)-sin(π/2)*sin(θ)=-μ*(cos(π)cos(θ)-sin(π)sin(θ)), we get -sin(θ)=-μ*(-cos(θ))."
+ },
+ {
+ "description": "Simplifying Equation to Solve for Maximum Wedge Angle",
+ "content": "Simplifying -sin(θ)=-μ*(-cos(θ)), we get tan(θ)=-μ."
+ },
+ {
+ "description": "Simplifying Equation to Solve for Maximum Wedge Angle",
+ "content": "Solving for θ, we get θ = atan(μ)."
+ }
+ ]
+ }
+ ]
+}